350. 两个数组的交集 II

/**
 * @param {number[]} nums1
 * @param {number[]} nums2
 * @return {number[]}
 */
var intersect = function (nums1, nums2) {
  const map = new Map()
  let result = []
  for (let i = 0; i < nums1.length; i++) {
    map.set(nums1[i], (map.get(nums1[i]) || 0) + 1)
  }
  for (let i = 0; i < nums2.length; i++) {
    if (map.has(nums2[i]) && map.get(nums2[i]) >= 1) {
      map.set(nums2[i], map.get(nums2[i]) - 1)
      result.push(nums2[i])
    }
  }
  return result
}